Location: PHPKode > scripts > Odds algorithm > odds-algorithm/example.php
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<title>Oods Algorithm</title>


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  <a class="tab" href="example.php">Example</a>
  <a class="tab" href="source.php">Class</a>
  <a class="tab" href="http://www.math.ucla.edu/~tom/Stopping/sr2.pdf" target="_blank">Theory</a>

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<h2> The good reasoned choice...</h2><br />

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<img src="images/thumb.png" alt="Khaled Al-Sham'aa" border="0" width="200" height="150" />
<span class="FirstChar">H</span>ow to make the good decision? A mathematical method of simple
formulation and easy application allows us to optimize our choices, in the everyday life as at 
the time of serious conflicts.
The problem is defined as a dynamic process that includes two decision makers (DMs) in the selection
of the same offer. A sequence of a prefixed number of (n) offers is observed, one at a time, randomly.
The arrival of offers does not follow any probability distribution. Hence, each DM should rank the
currently observed offers among those already observed. Two kinds of ranks follow: relative and absolute ranks.
At each stage of the dynamic process, an offer can be accepted or discarded. 
Each discarded offer cannot be re-examined in later stages. We assume that each DM 
has his individual utility and ranking for the selected offer. Since the rankings of 
the DMs are different, a conflict can arise when an offer is accepted by either DM and 
refused by his opponent. In this case, a stopping rule should be defined in order to avoid such situations.

<h2>Example Game Rules</h2>
Numbers are generated by sequences of random produced by independent draws from a given 
range (between 1 and 6 in this example). The law of drawing different numbers or expressions 
may be time-invariant (stationary) or else depend on time. For a fixed n (in this case n=12 available events) 
and a given pattern (here we are looking for appearance of number 6) our goal is to maximize the probability 
of stopping on the k(th) last appearance of number 6 (if any) in such events of total n, given that we must 
not return on a previous appearance of 6.


$x = new Oods(12, '1/6');

for($i=1; $i<=12; $i++){
    if(ceil(rand(0, 6)) == 6){ $good=true; }else{ $good=false; }

    list($accept, $w) = $x->doYouAccept();

    if($accept == true && !$select){
         $select = true;
         $chance = round($w*100, 0);
         echo "<li><b><font color='blue'>Accept in turn k=$i where chance to be the last appearance of number 6 is %$chance</font></b></li>";
        if($good && !$select) echo "<li><font color='green'>Number 6 has been appeared at turn k=$i, but we may get better!!</font></li>";
        if($good && $select)  echo "<li><font color='red'>Number 6 has been appeared again at turn k=$i ... we miss it :(</font></li>";

if(!$select) echo "<font color='red'>I am sorry, we loss all our chances!!</font><br />";

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