Location: PHPKode > scripts > ImageUpload > imageupload/example.php
<?php
if(isset($_POST['submit'])){


   if ($_FILES && !$_FILES['input_file']['error']) {

    require_once('fileUpload.php');
    $opts = (array)array();

    $opts['file'] = 'input_file';
    
    $imgUp = new imageUpload($opts);

    if($imgUp){
      if($imgUp->error >= 6){
        echo "Internal error 6. Please contact admin or try again later.";    //you can update log file with error for debugging
      }else{
        echo $imgUp->error; 
      }
    }else{
        echo "Internal error. Please contact admin or try again later.";      //you can update log file with error for debugging
    }
   }
}
?>


<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">

<html>

<head>
<title>Sans Titre</title>
<meta http-equiv="content-type" content="text/html; charset=iso-8859-1" />
</head>
<body bgcolor="#FFFFFF">
<?php
        echo '<form name="join" method="POST" action="example.php" enctype="multipart/form-data">';
        echo '<input name="input_file" type="file" value="Choose a file..." />';
        echo '<input type="submit" name="submit" value="Submit" />';
        echo '</form>';
?>
</body>

</html>
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